| [ October 13, 2003 ] [  Last update May 7, 2025 ] Tautonymic numbers
 I first read this name in one of Terry Trotter's webpageswhere he uses the number 5757 to present a new number format.
 The scientific name is commonly used in zoölogy for naming speciesin which the epithet for the species is the same as that of the genus.
 Some examples : the animal Gorilla gorilla ;
 the filarial worm Loa loa ;
 the greenfinch Chloris chloris ;
 the bank swallow Riparia riparia .
 
 Transferred to the world of numbers the analogy brings us tonumbers that can be split up into two equal non-palindromic halves
 and each part with at least two different digits.
 Otherwise we would have repdigits which are already wellknown.
 Note that these tautonymic numbers are all 'base related' since
 they are digit-dependent. Generalized tautonymic numbers are such
 numbers where more than two identical parts are allowed.
 Near tautonymic numbers (NTN) have equal length parts that differ
 by one. NTN's are the only tautonyms that can be prime !
 No better introduction to tautonymic numbers than pointing your attentionto a popular oldtimer from artists Zager and Evans with their song
 In the Year 2525  which is almost a tribute to this kind of numbers.
 Other tautonyms that appear in the song are
 3535, 4545, 6565 and 9595.
 5555 is excluded as it is a repdigit
 and 7510 together with 8510 don't serve our purpose either
 since not tautonymic at all, despite the fact that it seems
 that these should have been 7575 and 8585 in the logic of things
 but were almost certainly changed for lyrical reasons.
 This wonplate will collect tautonymic numbers that showinteresting properties or are curious in some way or other.
 Of course we stick to the recreational mathematical world.
 
 Allow me to start with the number of the song title 2525 itself.This number can be expressed with the nine digits 1 through 9 as follows :
  2525 = (92)4 + (78)5 + (61)3 → 924785613
  6565 = (25)8 + (43)7 + (96)1 → 258437961
 
 9595 when raised to the fourth power is a numberwhose eight distinct digits, in base 10,
 occur with the same frequency of two.
 95954 = 8475784699200625
 It is the largest solution in its class P4(8.2).
 An extract from my extraordinary squares and powers page.
13223140496_13223140496 = 363636363642
40495867769_40495867769 = 636363636372
 Enjoy the following neat fact that36363636364 * 63636363637 = 23140495868_23140495868
 is yet another superb tautonym !
 
 The 26th decagonal (10-sided polygonal) number is 2626 !(Sloane's A001107)
 
 A triangular tautonymic number
  5050 = the sum of the first 100 integers = (1002+100)/2 
 Interesting tautonyms with palindromic halves are allowed here:An extract from my Sum of Squares of SIX consecutive integers page.
191191 = 1762 + 1772 + 1782 + 1792 + 1802 + 1812
Two extracts from my Sum of Squares of ELEVEN consecutive integers page.
161161 = 1162 + 1172 + 1182 + 1192 + 1202 + 1212 + 1222 + 1232 + 1242 + 1252 + 1262
494494 = 2072 + 2082 + 2092 + 2102 + 2112 + 2122 + 2132 + 2142 + 2152 + 2162 + 2172 
  The string formed by concatenating the natural numbers from 7 to 7171 is probable prime.
 | C:\PFGW>pfgw -q"sm(7171,7)/10^len(sm(6))" PFGW Version 20040816.Win_Stable (v1.2 RC1a) [FFT v23.8]
 
 sm(7171,7)/10^len(sm(6)) is 3-PRP! (123.8595s+0.0219s)
 | 
 
 A Kaprekar tautonymic number
  7272 since 72722 = 5288_1984 and 5288 + 1984 = 7272 !
 
 9696 * 29696 + 9696 + 1 is prime.Note that 9696 is not only tautonymic but also strobogrammatic.
 (source: Prime Curios! 9696)
 
 The decimal expansion of 499499 ends with the digits 499499.(source: Prime Curios! 499)
 
 From the Prime Curios! database :For any 510510 consecutive integers,
 5760 will have 17 as a lowest prime factor. [Schuler]
 Note that 510510 equals 714 x 715, two successive numbers !
 Pomerance found that the product of 715*715-1 (510510) equaled
 the product of both their prime factors: 2*3*5*7*11*13*17. [McAlee]
 
 The smallest (probable) prime of 35631 digits is situated ata tautonymic displacement from the power of ten axis
 namely 1035630 + 239239
 
 188188 is a tautonymic cuberoot of an exclusionary cube. But there are more...188_1883 = 6664625956660672
 418_4183 = 73253955072930632
 488_4883 = 116563263575030272
 4442_44423 = 87673015533155613358888
 8988_89883 = 726305734421244276046272
 9522_95223 = 863604334140616884744648
 Can you find larger examples ?
 See at OEIS A029785 Ninedigits page 2
 
 The smallest number with exactly 240 divisors is 720720.Pari/GP code : for(i=1,oo, if(#divisors(i)==240,
 print(i," has exactly ",#divisors(i)," divisors");break()))
 
 Are you creative and adventurous enough to discovermore of these tautonymic numbers ?
 I will accept submissions until the year 2525...
 " If man is still alive.
 If woman can survive, they may find. "
 
 A calculation trick involving tautonyms.By Terry Trotter (†) - [ October 24, 2003 ]
 " Here is an old idea that may be worth considering.It's a calculation trick that appeals to, and often amazes, people
 who are not highly knowledgeable about number properties.
 The conversation between the magician and the patsy usually goes like this :
 The magician says : "Choose any 3-place number you wish and write it down." Let's say, by way of example, the patsy choose 276. Now the magician says : "Form a 6-place number by writing it beside itself." For our example, this means 276276. A tautonym has been produced. Magician : "Divide that result by 7." Result is 39468. Magician : "Divide that result by 11." Result is 3588. Magician : "Divide that result by 13, and report what you have." Of course, the patsy now has the original number, 276, once again !The trick is easily explained. Writing a 3-place number beside itself
 is equivalent to multiplying it by 1001. But 1001 = 7 x 11 x 13.
 So all the person is doing is dividing the large number by 7, 11 and 13,
 in order to arrive at the original 3-digit choice. Simple, yes.
 Profound, no. But it is interesting to many people for whom mathematics
 is a great mystery. And proving it makes a good school math activity. "
 
 Tautonymic numbers as products of two consecutives.By Patrick De Geest - [ October 28, 2003 ]
 Here is something that emerged while I was investigatingtautonymic numbers being the product of two consecutive integers.
 Playing around with tautonymic numbers I came across a
 well known 'prime' number P = 5882353. I say well known
 since this number made its entrance already in the following
 two puzzles pages.
 http://www.primepuzzles.net/puzzles/puzz_104.htm
 http://www.primepuzzles.net/puzzles/puzz_180.htm
 P = 5882353 = 5882 + 23532 Now multiply this famous prime with another famous prime '13'and we get 76470589 ! Call this number N and you will see
 that N times (N+1) equals 58477510_58477510, a tautonym !!!
 Moreover N = 76470589 when split into two halves andgiven the same treatment as P = 5882353 gives
 76472 + 05892 = 5882353 * 10 or ten times our initial P !!
 ps. 7647 + 2353 = 10000 exactlyIs there even more to discover in this curious topic ?
 ps. note also this infinite beast pattern363 * 364 = 132_132
 336633 * 336634 = 113322_113322
 333666333 * 333666334 = 111333222_111333222
 etc.
 and the next one was spotted by Jean Claude Rosa637 * 638 = 406_406
 663367 * 663368 = 440056_440056
 666333667 * 666333668 = 444000556_444000556
 etc.
 Tautonymic numbers of the form (N) * (N+1) 1. 132_132 = 363 * 3642. 406_406 = 637 * 638
 3. 510_510 = 714 * 715
 4. 852_852 = 923 * 924
 5. 7930_7930 = 8905 * 8906
 6. 66942_66942 = 81818 * 81819
 7. 113322_113322 = 336633 * 336634
 8. 440056_440056 = 663367 * 663368
 9. 5289256_5289256 = 7272727 * 7272728
 10. 58477510_58477510 = 76470589 * 76470590
 11. 111333222_111333222 = 333666333 * 333666334
 12. 164378892_164378892 = 405436668 * 405436669
 13. 183673470_183673470 = 428571429 * 428571430
 14. 200444410_200444410 = 447710185 * 447710186
 15. 206611570_206611570 = 454545454 * 454545455
 16. 224376732_224376732 = 473684211 * 473684212
 17. 277008310_277008310 = 526315789 * 526315790
 18. 297520662_297520662 = 545454546 * 545454547
 19. 305024040_305024040 = 552289815 * 552289816
 20. 326530612_326530612 = 571428571 * 571428572
 21. 353505556_353505556 = 594563332 * 594563333
 22. 444000556_444000556 = 666333667 * 666333668
 23. 479289942_479289942 = 692307693 * 692307694
 24. 506156050_506156050 = 711446449 * 711446450
 25. 581006406_581006406 = 762237762 * 762237763
 26. 695569506_695569506 = 834008097 * 834008098
 27. 739569252_739569252 = 859982123 * 859982124
 28. 772853520_772853520 = 879120879 * 879120880
 29. 814065240_814065240 = 902255640 * 902255641
 30. 948726600_948726600 = 974025975 * 974025976
 31. 962088780_962088780 = 980861244 * 980861245
 ( from here entries by JCR [ Nov 18, 2003 ] )
 32. 6431722380_6431722380 = 8019801980 * 8019801981
 33. 7157761512_7157761512 = 8460355496 * 8460355497
 34. 9138301710_9138301710 = 9559446485 * 9559446486
 35. 20050158756_20050158756 = 44777403627 * 44777403628
 36. 21419301960_21419301960 = 46280991735 * 46280991736
 37. 28857318490_28857318490 = 53719008265 * 53719008266
 38. 30495351502_30495351502 = 55222596373 * 55222596374
 39. 52431292270_52431292270 = 72409455370 * 72409455371
 40. 54631379962_54631379962 = 73913043478 * 73913043479
 41. 63689920156_63689920156 = 79805964787 * 79805964788
 42. 66112433920_66112433920 = 81309552895 * 81309552896
 43. 97015431556_97015431556 = 98496411892 * 98496411893
 JCR noticed also this nice '0n9n0n9n0n' pattern emerging from nr. 32 6431722380_6431722380 =8019801980 * 8019801981
 640319720239800_640319720239800 =800199800199800 * 800199800199801
 64003199720023998000_64003199720023998000 =80001999800019998000 * 80001999800019998001
 6400031999720002399980000_6400031999720002399980000 =8000019999800001999980000 * 8000019999800001999980001
 etc. The method used by JCR : T_T = T*(10^L+1) where L = number of digits of T.One searches for N such that N*(N+1) = T*(10^L+1) thus
 the largest primefactor of 10^L+1, P for example,
 divides N, or divides N+1. So it is sufficient to try N
 multiple of P or N+1 multiple of P. If by chance P is
 large enough the results are obtained very quick but for
 10^15+1, P = 9091 and so the progression isn't that rapid.
 
 JCR found all solutions of T_T = N*(N+1) up to 38 digits for T_T.There are a lot of solutions ! Too many to display all.
 So for T_T's of 24 digits and more I will restrict myself
 to list only the smallest and the largest.
 Here is an explanation why N or N+1 cannot be prime : 
We have : T_T = T*(10^L+1) = N*(N+1)The number T_T is written with 2*L digits so N is written
 obligatory with L digits hence :
 N <= 10^L1 (1)
 Suppose now that N is prime then N+1 is divisible by
 10^L+1 hence N+1 ⩾ 10^L+1 and so N ⩾ 10^L, which
 contradics the inequality (1).
 If N+1 is prime then N is divisible by 10^L+1,
 hence N ⩾ 10^L+1, which contradicts again inequality (1).
 
 Continuation of the table (smallest-largest only) :(by JCR [ Dec 2-4, 2003 ] )
 T_T with 24 digits : 5 solutions44. 111133332222_111133332222 = 333366663333 * 333366663334
 48. 928339282860_928339282860 = 963503649635 * 963503649636
 T_T with 26 digits : 4 solutions49. 2066115702480_2066115702480 = 4545454545455 * 4545454545456
 52. 5769181397602_5769181397602 = 7595512752673 * 7595512752674
 T_T with 28 digits : 11 solutions53. 11126290222882_11126290222882 = 33356094230113 * 33356094230114
 63. 96284719602360_96284719602360 = 98124777504135 * 98124777504136
 T_T with 30 digits : 91 solutions64. 101042810175330_101042810175330 =
 317872317409569 * 317872317409570
 154. 973101434819340_973101434819340 =
 986459038591740 * 986459038591741
 T_T with 32 digits : 17 solutions155. 1147227785472790_1147227785472790 =
 3387075117963565 * 3387075117963566
 171. 9020805170520430_9020805170520430 =
 9497791938403594 * 9497791938403595
 T_T with 34 digits : 11 solutions172. 12615748728591762_12615748728591762 =
 35518655279432753 * 35518655279432754
 182. 82736707922790756_82736707922790756 =
 90959720713506347 * 90959720713506348
 T_T with 36 digits : 5 solutions183. 111111333333222222_111111333333222222 =
 333333666666333333 * 333333666666333334
 187. 788169507760196310_788169507760196310 =
 887789112210887789 * 887789112210887790
 T_T with 38 digits : 2 solutions188. 1322314049586776860_1322314049586776860 =
 3636363636363636364 * 3636363636363636365
 189. 4049586776859504132_4049586776859504132 =
 6363636363636363636 * 6363636363636363637
 | Look carefully at the following phenomenom
13223140496_13223140496 = 363636363642
40495867769_40495867769 = 636363636372
and the two 38-digit solutions above indexed 188 & 189. No doubt you'll notice also that13223140496 is the rounded left part of 1322314049586776860
 as well as
 40495867769 is the rounded left part of 4049586776859504132
 Is there another pattern lurking...In the same spirit Jean Claude Rosa discovered [ Dec. 11, 2003 ]
81818 * 81819 = 66942 * (10^5 + 1)
81818181818181819 * 81818181818181820 =
66942148760330580 * (10^17 + 1)
and also
7272727 * 7272728 = 5289256 * (10^7+1)
727272727272728 * 727272727272729 =
528925619834712 * (10^15+1) JCR thinks one needs to consider this number : (90m)+1.Happy researching...Indeed if n=2*k+5 then 10^n+1 is divisible by (90m)+1 with m=k+2.
 In fact in that case we have 10^n+1 = 11 * ((90m)+1).
 | 
 
 Tautonymic numbers as products of three consecutives.
  K * (K+1) * (K+2) = T_T By Jean Claude Rosa - [ November 6, 2003 ]
 Thus far JCR only discovered one solution namely :76 * 77 * 78 = 456_456
 
 Near tautonymic numbers as products of two and more consecutives.
  K * (K+1) = (T)_(T ± 1) 
  K * (K+1) * (K+2) = (T)_(T ± 1) 
  K * (K+1) = (T)_(T ± 1)_(T ± 2) 
  etc. 1. 78 * 79 = 61_622. 80919 * 80920 = 65479_65480
 3. 91809 * 91810 = 84289_84290
 4. 326510 * 326511 = 106609_106610
 5. 475025 * 475026 = 225649_225650
 6. 524975 * 524976 = 275599_275600
 7. 673490 * 673491 = 453589_453590
 8. 4323777 * 4323778 = 1869505_1869506
 9. 4767132 * 4767133 = 2272555_2272556
 10. 5232868 * 5232869 = 2738291_2738292
 11. 5676223 * 5676224 = 3221951_3221952
 781340266 * 781340265 = 610492_610491_610490 19 * 20 * 21 = 79_80 13 * 12 * 11 = 17_16 Can you find larger/other examples ? 
 Near tautonymic numbers of the form (T)_(T + 1) as SQUARES. 1. 183_184 = 42822. 328_329 = 5732
 3. 528_529 = 7272
 4. 715_716 = 8462
 5. 6099_6100 = 78102
 6. 13224_13225 = 363652
 7. 40495_40496 = 636362
 8. 106755_106756 = 3267342
 9. 453288_453289 = 6732672
 10. 2066115_2066116 = 45454542
 11. 2975208_2975209 = 54545472
 12. 22145328_22145329 = 470588232
 13. 28027683_28027684 = 529411782
 14. 110213248_110213249 = 3319838072
 15. 110667555_110667556 = 3326673342
 16. 147928995_147928996 = 3846153862
 17. 178838403_178838404 = 4228928982
 18. 226123528_226123529 = 4755244772
 19. 275074575_275074576 = 5244755242
 20. 333052608_333052609 = 5771071032
 21. 378698224_378698225 = 6153846152
 22. 445332888_445332889 = 6673326672
 23. 446245635_446245636 = 6680161942
 24. 518348515_518348516 = 7199642462
 25. 574930563_574930564 = 7582417582
 26. 647238399_647238400 = 8045112802
 27. 657515568_657515569 = 8108733372
 28. 734693880_734693881 = 8571428592
 29. 801777640_801777641 = 8954203712
 30. 826446280_826446281 = 9090909092
 31. 897506928_897506929 = 9473684232
 32. 898802499_898802500 = 9480519502
 33. 924910143_924910144 = 9617224882
 ( from here entries by JCR [ Nov 26, 2003 ] )
 34. 1568473680_1568473681 = 39603960412
 35. 3647681599_3647681600 = 60396039602
 36. 4789624063_4789624064 = 69207109922
 37. 8315420899_8315420900 = 91188929702
 38. 13973312520_13973312521 = 373808942112
 39. 16311962328_16311962329 = 403880704272
 40. 20087347599_20087347600 = 448189107402
 41. 22873345935_22873345936 = 478260869562
 42. 27221172024_27221172025 = 521739130452
 43. 30449526120_30449526121 = 551810892612
 44. 35535821475_35535821476 = 596119295742
 45. 39211524099_39211524100 = 626191057902
 46. 80200635024_80200635025 = 895548072552
 47. 85677207840_85677207841 = 925619834712
 48. 94076078655_94076078656 = 969928237842
 49. 111066675555_111066675556 = 3332666733342
 50. 444533328888_444533328889 = 6667333266672
 51. 547194595608_547194595609 = 7397260273972
 52. 859342532899_859342532900 = 9270072992702
 ***
 A nice pattern emerges from this list (see nrs. 3, 9 & 22)
 528_529 = 7272
 453288_453289 = 6732672
 445332888_445332889 = 6673326672
 
 (4n)5(3n)2(8n)8_(4n)5(3n)2(8n)9 = (6n)7(3n)2(6n)72  Among the first 33333 values of n [ PDG, July 12, 2004 ] only 0, 16, 17, 33, 2738, 3096 yield primes.
 The last two are of course only probable primes of titanic
 lengths 8217 and 9291 resp. ( using the formula 3*n+3 ).
 Now that length 100000 is crossed the search has stopped.
  The squareroot is an intertwining of 727  with another palindrome 6n3n6n !
  Palindrome 909090909 (with nine digits btw!) squared harbours another palindrome twice only composed of even digits.
 9090909092 = (82644628)0_(82644628)1
 Note also that 82644628 * 11 + 1 = 909090909
 ***
 Another nice pattern from JCR this time (see nrs. 0, 8, 15 & 49)
 075_076 = 2742
 106755_106756 = 3267342
 110667555_110667556 = 3326673342
 111066675555_111066675556 = 3332666733342
 (1n)0(6n)7(5n)5_(1n)0(6n)7(5n)6 = (3n)2(6n)7(3n)42Note that the squareroot is an intertwining of
 274  with palindrome 3n6n3n !
 xxx
  727  +  274  =  1001  a palindrome  727  x  274  =  199_198  a tautonym of the form (T)_(T  1) Jean Claude Rosa found many new patterns : 3(9n)6(0n)3(9n)6(0n)4(0m)12 with n odd and m = n-1but alas, this number always seems to be divisible by 7.
 Fascinating 90909090909112 ! Indeed, because JCRdiscovered that this number is the first of yet another pattern !
 Here it is :
 If P = (90n)9112 with n = 11*k+5 then P^2 = T_(T+1)
 PFGW was executed up to n = 50396 [ PDG, July 24, 2004 ]
 Only one other probable prime (or PRP) with less
 than 100000 digits popped up after the
 first one with k = 0 and so n = 5 giving P = 9090909090911
 whose square equals 8264462809920_8264462809921 .
 Note the recurrent palindromic substrings in the expressions :
 E.g. with 909090909090909090909090909090909112 =
 82644628099173553719008264462809920_82644628099173553719008264462809921
 This second probable prime is with k = 3219 and so n = 35414
 and has 70831 digits in total, a personal record !
  Two more patterns which, JCR hopes, might give better results :
 P=(54n)7 avec n = 11*k+3One probable prime was found for n = 410 :
 r(410,54)*10+7 is 3-PRP! (0.0542s+0.0171s)
 A prime of only 821 digits.
 I pushed the pattern up to n = 50064 [ PDG, July 31, 2004 ]
 but alas no new candidate showed up below digitlength 100000 !
 P=(72n)7 with n = 11*k+1Isn't this one particularly beautiful ?
 Indeed a nice one and also known as a SUPP or
 'Smoothly Undulating Palindromic Prime'.
 Hans Rosenthal checked all probable primes candidates up to
 40000 digits and I continued
 up to 100001 [ PDG, September 13, 2004 ].
 See reference table at undulat.htm
 and go to section 727. None of the numbers in the table
 are of the form  11*k+1. Pity :(
 
 Near tautonymic numbers of the form (T)_(T  1) as SQUARES. 1. 82_81 = 9122. 8242_8241 = 90792
 3. 9802_9801 = 99012
 4. 538277_538276 = 7336742
 5. 998002_998001 = 9990012
 6. 77837026_77837025 = 882252952
 7. 99980002_99980001 = 999900012
 ( from here entries by JCR [ Nov 27, 2003 ] )
 8. 7922547265_7922547264 = 89008692082
 9. 8643251345_8643251344 = 92969088122
 10. 9223797610_9223797609 = 96040603972
 11. 9999800002_9999800001 = 99999000012
 12. 106710893290_106710893289 = 3266663332672
 13. 453378226757_453378226756 = 6733336667342
 14. 491023832065_491023832064 = 7007309270082
 15. 945958034530_945958034529 = 9726037397272
 16. 999998000002_999998000001 = 9999990000012
 discover with JCR this 'joli' pattern (see nrs. 1, 3, 5, 7, 11 & 16) (9n)8(0n)2_(9n)8(0n)1 = (9n+1)(0n)12xxx
 
 Add the square roots of index nrs. 12 & 13 to discover
 326666333267 + 673333666734 = 1000000000001 their palindromic sum ! 326666333267 * 673333666734 = 219955439977_219955439978 their product a near_tautonymic number of the form (T)_(T+1) ! | Puzzle 258.  Primes and sibling numbers-II http://www.primepuzzles.net/puzzles/puzz_258.htm
 
 Jean Claude Rosa found the following result : If p^2 = a.(a-1) then the length of p is an even number.Proof: We want : p^2 = a.(a-1) Let L=length of a=length of (a-1)=length of p
 So we have : p^2 = a*10^L+a-1
 p^2 = a*(10^L+1)-1
 If d is a prime divisor of 10^L+1, we have:
 p^2 = (-1) mod d, that is to say:
 p^2 = d-1 mod d (1)
 If L is an odd number we have (10^L+1)=0 mod 11
 and the equality (1) implies that we must have: p^2 = 10 mod 11.
 But this last equality has no solution. The number 10 is not a
 quadratic residu modulo 11.
 Conclusion : L is an even number.
 In order to find a number p such that : p^2 = a.(a-1)
 we can use the equality (1) : p^2 = d-1 mod d
 Method: 1°) Take for d the largest prime divisor of 10^L+1
 2°) Calculate the smallest value R ( 1⩽R⩽(d-1)/2
 such that R^2 = d-1 mod d
 3°) The number p is p = k*d+R or p = k*d+d-R
 
 | 
 The first pattern I investigated is (9[n])(0[n-1])(1)2.These numbers are prime only for the next four cases: n = 2, 4, 6 & 8.
 None others below n = 50000 (PDG)!
This number has some historical
 trace as for instance the pattern for n = 2, 4, 6 & 8
 appeared in Beiler's book (table 42 p. 85):
 http://primes.utm.edu/curios/page.php?short=999999000001
 and also
 http://primes.utm.edu/curios/page.php?short=9901
 Regarding p^2 = T_(T-1) here is a pattern (again by JCR!)(he wrote: "a bit complicated but one does as he sees fit")
 (3k)2(6n)(3w)2(6k)72 with n = 2*k+2, w = 2*k+1
 Examples:
 326666333267
 332666666333332667
 333266666666333333326667
 and so on...
 Here is the current state of affairs for the above
 sibling-II pattern.
 3-PRP! for the following values of k :
 k = 9, 13, 40, 363 & 6305
 none other below k = 16666 (PDG, length > 100000).
 For k = 363 the total length (6*k+6) is 2184 digits.
 For k = 6305 the numberlength is thus 37836 digits.
 For Question Q2 of Puzzle 258 this is the best shot so far.
 My first gigantic near-tautonymic number of the form p^2 = (T+1)_(T).
 
 
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