World!Of Numbers |
![]() ![]() |
||
[ August 12, 1999 ] when taken into consideration the following two rules : First, the digit zero may not appear in the palindrome Secondly, the sum of its digits equals the number of its prime factors 21312 = 2 + 1 + 3 + 1 + 2 = 9 so there should exist nine prime factors ! Indeed as 21312 = 2 x 2 x 2 x 2 x 2 x 2 x 3 x 3 x 37. Dear puzzlers, proof me wrong by finding a second solution... P.S. 21312 is also the largest substring in 249 or 562949953421312 ( A046260 ) | |||
![]() ![]() ![]() ![]() ![]() ![]() ![]() ![]() |
[ TOP OF PAGE]