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Some beautiful patterns resulting in palindromes

After an exercice on Sloane's integer sequences A048611 and A048612 [ June 27, 1999 ]
originally submitted by Felice Russo with description
[ Least solutions for 'Difference between two squares is a repunit of length n' ]
I discovered that some beautiful patterns resulting in palindromes could be constructed.

        62 – 52 = 11
      662 – 652 = 131
    6662 – 6652 = 1331
  66662 – 66652 = 13331
666662 – 666652 = 133331

        62 – 52 = 11
      562 – 452 = 1111
    5562 – 4452 = 111111
  55562 – 44452 = 11111111
555562 – 444452 = 1111111111

            562 – 552 = 111
        50562 – 50452 = 111111
    5005562 – 5004452 = 111111111
500055562 – 500044452 = 111111111111
All numbers are palindromes in the next
'nec plus ultra' (one infinite and one finite) marvelous patterns!
            62 – 52 = 11
        6562 – 5652 = 111111
    656562 – 565652 = 1111111111
65656562 – 56565652 = 11111111111111

        62 – 52 = 11
      662 – 552 = 1331
    6662 – 5552 = 135531
  66662 – 55552 = 13577531
666662 – 555552 = 1357997531

P.S. Note the following observations

65656 + 56565 = 122221 a palindrome
65656 – 56565 = 9091 = 09_09_1 = 1n1n1

1n1n1 is a pseudopalindrome ( n = –1 hence 1n = 10–1 = 09 )


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