[ May 15, 1998 ]
19291 and 124060421
constitute a remarkable palindromic duo

Form the numerator as follows : n*(n+1)*(n+2).
Form the denominator as follows : n+(n+1)+(n+2).

Now replace 'n' with our remarkable palindrome 19291 and finish the division.

19291 * 19292 * 19293 19291 + 19292 + 19293	7180120925796 57876	= 124060421

Moreover we see that 124060421 divided by 19291 = 6431 exactly !
19291 has two palindromic prime factors : 101 x 191 !
n+(n+1) = 19291 + 19292 = 38583 again another palindrome.

See also Sloane's entry A032789

The same can be done when we replace 'n' with 9, 99, 999, 9999, ...
The resulting palindromes will be the series 33, 333, 3333, 33333, ...